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Quoting, variables, and xterm
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graftonfot@yahoo.com
*nix forums beginner


Joined: 23 Mar 2006
Posts: 3

PostPosted: Thu Jul 20, 2006 2:26 pm    Post subject: Quoting, variables, and xterm Reply with quote
Hello,

I believe I understand quoting and variables at least to a basic
degree, but I wonder if anyone could help me with the following.

We have a bash script which contains a function which uses its
arguments to launch any specified command in a new xterm. It looks
similar to:

function xterm_start {
prog=$1
title=$2
xterm -title $title -e $prog &

}

(there are other arguments for geometry and size, but I've left those
out for simplicity.)

Usually this function is passed the name of an executable shell script.


What I would like to be able to do is to pipe the stdout (and stderr)
of whatever command is passed in (as $1) through a tee, but I cannot
seem to find the right syntax to pass as xterm's -e parameter.

Quote:
From what I could find, using a new shell is the right approach here,
as in


xterm -e 'sh -c myprog 2>&1 | tee myprog.out'

....but I can't seem to be able to build a string like this using the
variable value(s). The closest I've seem to come was to use code that
looked like:

cmd="'sh -c $prog 2>&1 | tee $prog.out'"

(those are single quotes nested inside double quotes)

Using this code, with "myprog" as the value of $prog, an echo $cmd
yielded:

'sh -c myprog 2>&1 | tee myprog.out'

which looks right, but then xterm -e $cmd failed (as does xterm -e
"$cmd" and xterm -e '$cmd')

Is this possible, if so, what would be a good approach?

Thanks.
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Bill Marcum
*nix forums Guru


Joined: 28 Mar 2005
Posts: 1264

PostPosted: Thu Jul 20, 2006 5:52 pm    Post subject: Re: Quoting, variables, and xterm Reply with quote
On 20 Jul 2006 07:26:59 -0700, graftonfot@yahoo.com
<graftonfot@yahoo.com> wrote:
Quote:

Using this code, with "myprog" as the value of $prog, an echo $cmd
yielded:

'sh -c myprog 2>&1 | tee myprog.out'

which looks right, but then xterm -e $cmd failed (as does xterm -e
"$cmd" and xterm -e '$cmd')

eval xterm -e $cmd (or "$cmd"?)




--
All life evolves by the differential survival of replicating entities.
-- Dawkins
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Chris F.A. Johnson
*nix forums Guru


Joined: 20 Feb 2005
Posts: 2268

PostPosted: Thu Jul 20, 2006 7:22 pm    Post subject: Re: Quoting, variables, and xterm Reply with quote
On 2006-07-20, graftonfot@yahoo.com wrote:
Quote:
Hello,

I believe I understand quoting and variables at least to a basic
degree, but I wonder if anyone could help me with the following.

We have a bash script which contains a function which uses its
arguments to launch any specified command in a new xterm. It looks
similar to:

function xterm_start {
prog=$1
title=$2
xterm -title $title -e $prog &

}

(there are other arguments for geometry and size, but I've left those
out for simplicity.)

Usually this function is passed the name of an executable shell script.


What I would like to be able to do is to pipe the stdout (and stderr)
of whatever command is passed in (as $1) through a tee, but I cannot
seem to find the right syntax to pass as xterm's -e parameter.

From what I could find, using a new shell is the right approach here,
as in

xterm -e 'sh -c myprog 2>&1 | tee myprog.out'

...but I can't seem to be able to build a string like this using the
variable value(s). The closest I've seem to come was to use code that
looked like:

cmd="'sh -c $prog 2>&1 | tee $prog.out'"

cmd="$prog 2>&1 | tee \"$prog.out\""

Quote:
(those are single quotes nested inside double quotes)

Get rid of them.

Quote:
Using this code, with "myprog" as the value of $prog, an echo $cmd
yielded:

'sh -c myprog 2>&1 | tee myprog.out'

which looks right, but then xterm -e $cmd failed (as does xterm -e
"$cmd" and xterm -e '$cmd')

xterm -e "$cmd"

--
Chris F.A. Johnson, author <http://cfaj.freeshell.org>
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
===== My code in this post, if any, assumes the POSIX locale
===== and is released under the GNU General Public Licence
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Google
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