string comparision

priyanka · *nix forums beginner Joined: 01 Jun 2006 Posts: 10

Hi there,

I am trying to compare two strings. But I am not able to do so. I use
:
if(function_name[function_number] == function_label[k]){

but this does not work.

I have written down my code:

const char *function_name[(code_addr_t)code_size];
string function_label[(code_addr_t)code_size];
int function_number = 0;
int i = 0;

ifstream inputStream("no_args.txt");
if(!inputStream)
die();

while(!inputStream.eof())
{
getline(inputStream,funcName);
i++;
function_label[i] = funcName;
}

int tot_func = i;

function_number = function_number + 1;
function_name[function_number] = "sumarray";

for(int k = 1; k <=tot_func;k++){
if(function_name[function_number] == function_label[k]){
printf("inside if\n");
}

The execution never enters inside the if { printf("insde if\n");

Thank you in advance,
priya

Ben Pfaff · *nix forums Guru Joined: 08 Apr 2005 Posts: 661

"priyanka" <priyankabhar@gmail.com> writes:

Google